Here's a Java program that demonstrates how to pass a method call as an argument to another method:

public class MethodAsArgumentExample {

    public static void main(String[] args) {
        int x = 5;
        int y = 7;
        int result = calculate(x, y, MethodAsArgumentExample::sum);
        System.out.println("Result: " + result);
    }
    
    public static int sum(int a, int b) {
        return a + b;
    }
    
    public static int calculate(int a, int b, IntBinaryOperator operator) {
        return operator.applyAsInt(a, b);
    }
}

Explanation:

The program defines three methods: main, sum, and calculate.

The sum method takes two integers as input and returns their sum.

The calculate method takes two integers and an IntBinaryOperator object as input. The IntBinaryOperator interface defines a single method, applyAsInt, which takes two integers as input and returns an integer. The calculate method calls the applyAsInt method of the IntBinaryOperator object, passing in the two integer arguments.

The main method declares two integer variables, x and y, and assigns them the values 5 and 7, respectively. It then calls the calculate method, passing in x, y, and a reference to the sum method using the MethodAsArgumentExample::sum syntax. The calculate method calls the applyAsInt method of the IntBinaryOperator object, which is the sum method in this case, passing in the two integer arguments x and y. The sum method returns the sum of the two integers, which is then returned by the calculate method. Finally, the main method prints the result to the console.

Note that by passing a method reference as an argument, the program is able to define the operation to be performed on the input values dynamically, without having to modify the calculate method itself. This makes the code more flexible and reusable.