Java 从 servlet 访问 WebContent 中的文件
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Access file inside WebContent from servlet
提问by Thirunavukkarasu Muthuswamy
I trying to access the html files inside the WebContent/alerts folder using its relative path from servlet. But i unable to access it using its relative path,
我尝试使用来自 servlet 的相对路径访问 WebContent/alerts 文件夹中的 html 文件。但我无法使用其相对路径访问它，
Access the file inside WebContent from Servletusing relative path:
使用相对路径从Servlet访问 WebContent 中的文件：
protected Element getSummary(String value) throws IOException
{
Element element=null;
Summary summary = Summary.valueOf(value);
switch(summary) {
case rtp_summary:
element=parseDIV(new File("../../WebContent/alerts/rtp_bcklg_mail.html"),"rtp_summary");
break;
case ffu_summary:
element=parseDIV(new File("/../../WebContent/alerts/ffu_comp_bcklg_mail.html"),"ffu_summary");
break;
default:
System.out.println("Enter a valid choice");
break;
}
return element;
}
Access the file inside WebContent from Java Threadusing relative path:
使用相对路径从Java Thread访问 WebContent 中的文件：
public class WriteJSONFile implements Runnable{
WriteJSONFile(){
}
@Override
public void run()
{
try {
createJSONFile();
} catch (IOException e) {
e.printStackTrace();
}
}
@SuppressWarnings("unchecked")
private static void createJSONFile() throws IOException
{
String path="C:/Users/Thiru/Documents/Website Design/Macaw/";
JSONArray jsonArray=new JSONArray();
JSONObject rtpStatus=new JSONObject();
rtpStatus.put("name","RTP");
rtpStatus.put("status",parseDIV(new File(path+"WebContent/alerts/rtp_bcklg_mail.html"),"rtp_health"));
jsonArray.add(rtpStatus);
JSONObject proposalattribStatus=new JSONObject();
proposalattribStatus.put("name","PROPOSAL ATTRIBUTE");
proposalattribStatus.put("status",parseDIV(new File(path+"WebContent/alerts/prpsl_txtsrch.html"),"prpsl_attrb_health"));
jsonArray.add(proposalattribStatus);
writetoFile(jsonArray);
}
private static void writetoFile(JSONArray jsonArray) {
try {
String path="C:/Users/Thiru/Documents/Website Design/Macaw/";
FileWriter file = new FileWriter(path+"WebContent/properties/status.json");
file.write(jsonArray.toJSONString());
file.flush();
file.close();
} catch (IOException e) {
e.printStackTrace();
}
}
protected static String parseDIV(File input, String divElement)
throws IOException {
Document doc = Jsoup.parse(input, "UTF-8");
String content = doc.getElementById(divElement).val();
System.out.println(divElement +" "+content);
return content;
}
}
}
And i also want to access the files inside Webcontent from RESTful web service method using relative path. Thanks in advance.
而且我还想使用相对路径从RESTful Web 服务方法访问 Webcontent 中的文件。提前致谢。
采纳答案by dnault
Use ServletContext.getRealPath()to locate the file on disk. Note that this only works if the webapp is "exploded" during deployment.
使用ServletContext.getRealPath()定位磁盘上的文件。请注意，这仅在 webapp 在部署期间“爆炸”时才有效。
For example:
例如：
File f = new File(getServletContext().getRealPath("alerts/rtp_bcklg_mail.html"));
回答by dnault
Current location of your files could be considered as a security issue. It is advisable to place such files in WEB-INF.
您文件的当前位置可能被视为安全问题。建议将此类文件放在WEB-INF.
String filePath = getServletContext().getRealPath("/WEB-INF/alerts/rtp_bcklg_mail.html");
回答by balu
Properties props=new Properties();
props.load(this.getServletContext().getResourceAsStream("/alerts/"+your_fileName+".html"));
by Calling ServletContext object we can get WebContext root from now on wards we can pass our file file statically
通过调用 ServletContext 对象，我们可以从现在开始获取 WebContext 根，我们可以静态地传递我们的文件
回答by moett
You can use servlet url pattern in your html page form action or html page a href tag.But your web.xml use servlet-mapping's url pattern like this (/projectname/servleturl)
您可以在 html 页面表单操作中使用 servlet url 模式或在 html 页面中使用 href 标签。但是您的 web.xml 使用 servlet-mapping 的 url 模式，如下所示 (/projectname/servleturl)
