In doGet Method use Gson jarLibrary to generate JSON response

在 doGet 方法中使用 Gson jarLibrary 生成 JSON 响应

like below

像下面

Gson gson = new Gson();
HashMap map = new HashMap();

map.put("MyApp",object);

String jsonString = gson.toJson(map);
PrintWriter writer = response.getWriter();
writer.print(jsonString);

You can make use of Google's JSON library GSON, for parsing and forming of the JSON string.It eases your life. Look at the following link for reference. http://viralpatel.net/blogs/creating-parsing-json-data-with-java-servlet-struts-jsp-json/

您可以使用谷歌的 JSON 库 GSON 来解析和形成 JSON 字符串。它让您的生活更轻松。查看以下链接以供参考。 http://viralpatel.net/blogs/creating-parsing-json-data-with-java-servlet-struts-jsp-json/

You can also refer to the following link http://nareshkumarh.wordpress.com/2012/10/11/jquery-ajax-json-servlet-example/

您也可以参考以下链接http://nareshkumarh.wordpress.com/2012/10/11/jquery-ajax-json-servlet-example/

You say you want to pass some parameters from the client to the server, but show both a JSON message and then your servlet code looks as though the parameters are passed with request.

您说您想将一些参数从客户端传递到服务器，但同时显示 JSON 消息，然后您的 servlet 代码看起来好像参数是随请求传递的。

If you intend to pass JSON in the request body, the server will not automatically parse this for you, so your calls request.getParameter("appID")and request.getParameter("appPwd")won't work.

如果您打算通过JSON的请求体，则服务器将不会自动解析这个给你，所以你的电话request.getParameter("appID")和request.getParameter("appPwd")将无法正常工作。

Instead you'll need to parse the body like this (based on the example message above):

相反，您需要像这样解析正文（基于上面的示例消息）：

JsonObject jsonRequest = Json.createReader(request.getInputStream()).readObject();

JsonObject authenticationRequestData = jsonRequest
  .getJsonObject("MyApp")
  .getJsonObject("requestPayload")
  .getJsonObject("body")
  .getJsonObject("request")
  .getJsonObject("MyTestApp")
  .getJsonObject("data")
  .getJsonObject("AuthenticationRequestData");

App app = new App();
app.setAppID(authenticationRequestData.getJsonString("appID"));
app.setAppPassword(authenticationRequestData.getJsonString("appPwd"));     

Once your servlet has the object you want to use to create a response, you can simply generate the JSON and write it using HttpServletResponse.getWriter()like this:

一旦您的 servlet 拥有您想要用来创建响应的对象，您就可以简单地生成 JSON 并使用HttpServletResponse.getWriter()如下方式编写它：

SomeObject someObject = app.doSomething();

JsonObject jsonObject = Json.createObjectBuilder()
 .add("someValue", someObject.getSomeValue())
 .add("someOtherValue", someObject.getSomeOtherValue())
 .build();

response.setContentType("application/json");
Json.createJsonWriter(response.getWriter()).writeObject(jsonObject);

You could create a Java Object that is formatted in the same format and then just use the built in methods

您可以创建一个格式相同的 Java 对象，然后只使用内置方法

@WebServlet(urlPatterns = {"/BasicWebServices"})
public class BasicWebServices extends HttpServlet{

    private static final long serialVersionUID = 1L;
    private static GsonBuilder gson_builder = new GsonBuilder().serializeNulls().setDateFormat("MM/dd/yyyy");
    public BasicWebServices(){
        super();
    }
    @Override
    public void destroy(){
          super.destroy();
    }
    @Override
    public void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException{
        doPost(request, response);
    }
    @Override
    public void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException{
        try{
            Gson gson = BasicWebServices.gson_builder.create();
            MyObject myObject = new MyObject();
            response.getWriter().write(gson.toJson(myObject));
        }
        catch(Exception e){
            response.getWriter().write("ERROR");
        }
    }
 }

Then you just have to make your MyObject the same setup as your retrieved values. Either make an object that is setup the same, or if you can use the same java class as the one sending it if possible.

然后，您只需将 MyObject 设置为与检索到的值相同的设置。要么创建一个设置相同的对象，要么尽可能使用与发送它相同的 java 类。

For your's you would have to have a class MyApp and then have the objects mAppHeader and requestPayload

对于你的，你必须有一个 MyApp 类，然后有对象 mAppHeader 和 requestPayload

public class mAppHeader(){
    String appId = "";
    String personId = "";
    String serviceName = "";
    String clientIP = "";
    String requestTimeStamp = "";     
    String encoding = "";
    String inputDataFormat = "";
    String outputDataFormat = "";
    String environment = "";
}